Function to determine required sample size to be within a given margin of error.
nsize(b, sigma = NULL, p = 0.5, conf.level = 0.95, type = "mu")the desired bound.
population standard deviation. Not required if using type
"pi".
estimate for the population proportion of successes. Not required
if using type "mu".
confidence level for the problem, restricted to lie between zero and one.
character string, one of "mu" or "pi", or just the
initial letter of each, indicating the appropriate parameter. Default value
is "mu".
Returns required sample size.
Answer is based on a normal approximation when using type "pi".
nsize(b=.03, p=708/1200, conf.level=.90, type="pi")
#>
#> The required sample size (n) to estimate the population
#> proportion of successes with a 0.9 confidence interval
#> so that the margin of error is no more than 0.03 is 728 .
#>
#>
# Returns the required sample size (n) to estimate the population
# proportion of successes with a 0.9 confidence interval
# so that the margin of error is no more than 0.03 when the
# estimate of the population propotion of successes is 708/1200.
# This is problem 5.38 on page 257 of Kitchen's BSDA.
nsize(b=.15, sigma=.31, conf.level=.90, type="mu")
#>
#> The required sample size (n) to estimate the population
#> mean with a 0.9 confidence interval so that the margin
#> of error is no more than 0.15 is 12 .
#>
#>
# Returns the required sample size (n) to estimate the population
# mean with a 0.9 confidence interval so that the margin
# of error is no more than 0.15. This is Example 5.17 on page
# 261 of Kitchen's BSDA.